Find the remainder when P(x) = 4x^3 + (1)x + (-8) is divided by x – (1).
Note
Apply the Remainder Theorem carefully. When a polynomial P(x) is divided by x - a, the remainder is P(a). Here the divisor is x - (1), so substitute x = 1 into the polynomial. P(1) = 4(1)^3 + (1)(1) + (-8) = 4 + 1 + -8 = -3. Therefore the remainder is -3.