For the quadratic equation x^2 + (-3)x + -1 = 0, determine the nature of its roots.
Note
Think of this as a discriminant question. For a quadratic equation ax^2 + bx + c = 0, first identify a = 1, b = -3, and c = -1. Now calculate D = b^2 - 4ac = (-3)^2 - 4(1)(-1) = 13. Since D > 0, the equation has two distinct real roots. Because it is positive but not a perfect square, the two real roots are irrational.
