For z=6+1i, find z·conjugate(z).
Note
For a complex number z = a + bi, multiplying by its conjugate gives z·conjugate(z) = a² + b². This is the square of the modulus, so it is always non-negative. Here a = 6 and b = 1. Therefore z·conjugate(z) = (6)² + (1)² = 36 + 1 = 37. So the correct answer is 37.
