In an arithmetic progression, first term a=-1 and common difference d=3. Find the sum of the first 12 terms.
Note
For an arithmetic progression, do not add all the terms one by one; use the AP sum formula. First identify the first term a, the common difference d, and the number of terms n. The sum is S_n=n/2[2a+(n-1)d]. Thus S_12=12/2[2(-1)+(12-1)(3)]=186. So the required sum is obtained directly from the formula after substitution.