If the prime factorization of n is 2^3 × 3^2 × 5, what is the number of positive divisors of n?
Note
Number of divisors = (3+1)(2+1)(1+1) = 4·3·2 = 24 using the exponents-plus-one rule.
If the prime factorization of n is 2^3 × 3^2 × 5, what is the number of positive divisors of n?
Number of divisors = (3+1)(2+1)(1+1) = 4·3·2 = 24 using the exponents-plus-one rule.