What is the vertex of y = 5(x + 1)^2 + 0?
Note
This quadratic is already written in vertex form. In y = a(x - h)^2 + k, the vertex is (h, k). Be careful with the sign inside the bracket: (x + 1) means h = -1, while (x - 1) means h = 1. Reading the values from y = 5(x + 1)^2 + 0, the vertex is (-1, 0). Therefore, the correct answer is (-1, 0).
