What is the vertex of y = 1(x – 5)^2 + 1?
Note
In y = a(x-h)^2+k, the vertex is (h,k). Therefore the vertex is (5, 1).
What is the vertex of y = 1(x – 5)^2 + 1?
In y = a(x-h)^2+k, the vertex is (h,k). Therefore the vertex is (5, 1).