What is the vertex of y = 5(x – 1)^2 – 4?
Note
In y = a(x-h)^2+k, the vertex is (h,k). Therefore the vertex is (1, -4).
What is the vertex of y = 5(x – 1)^2 – 4?
In y = a(x-h)^2+k, the vertex is (h,k). Therefore the vertex is (1, -4).