Think of this as a discriminant question. For a quadratic equation ax^2 + bx + c = 0, first identify a = 1, b = -9, and c = -7. Now calculate D = b^2 - 4ac = (-9)^2 - 4(1)(-7) = 109. Since D > 0, the equation has two distinct real roots. Because it is positive but not a perfect square, the two real roots are irrational.