For the quadratic equation x^2 + (-6)x + -4 = 0, determine the nature of its roots.
Note
Think of this as a discriminant question. For a quadratic equation ax^2 + bx + c = 0, first identify a = 1, b = -6, and c = -4. Now calculate D = b^2 - 4ac = (-6)^2 - 4(1)(-4) = 52. Since D > 0, the equation has two distinct real roots. Because it is positive but not a perfect square, the two real roots are irrational.
