What is the highest power of 2 that divides 160 evenly (i.e., the largest 2^k that is a factor of 160)?
Note
Prime factorize 160 = 16 × 10 = 2^4 × (2 × 5) = 2^5 × 5, so the highest power of 2 dividing 160 is 2^5 = 32.
What is the highest power of 2 that divides 160 evenly (i.e., the largest 2^k that is a factor of 160)?
Prime factorize 160 = 16 × 10 = 2^4 × (2 × 5) = 2^5 × 5, so the highest power of 2 dividing 160 is 2^5 = 32.