For a geometric progression with first term -3 and common ratio 3, find the sum of the first 6 terms.
Note
For a geometric progression, each term is multiplied by the same common ratio. Since this question asks for a sum, use the finite GP sum formula rather than adding terms manually. For r≠1, S_n=a(r^n-1)/(r-1). Hence S_6=-3((3)^6-1)/(3-1)=-1092. Keep the sign of the first term and the ratio carefully, because they control whether the sum is positive or negative.
