For z=-2+2i, find z·conjugate(z).
Note
For a complex number z = a + bi, multiplying by its conjugate gives z·conjugate(z) = a² + b². This is the square of the modulus, so it is always non-negative. Here a = -2 and b = 2. Therefore z·conjugate(z) = (-2)² + (2)² = 4 + 4 = 8. So the correct answer is 8.
