Find the remainder when P(x) = 3x^3 + (3)x + (-6) is divided by x – (-3).
Note
Apply the Remainder Theorem carefully. When a polynomial P(x) is divided by x - a, the remainder is P(a). Here the divisor is x - (-3), so substitute x = -3 into the polynomial. P(-3) = 3(-3)^3 + (3)(-3) + (-6) = -81 + -9 + -6 = -96. Therefore the remainder is -96.
