Think of this as a discriminant question. For a quadratic equation ax^2 + bx + c = 0, first identify a = 1, b = -10, and c = -8. Now calculate D = b^2 - 4ac = (-10)^2 - 4(1)(-8) = 132. Since D > 0, the equation has two distinct real roots. Because it is positive but not a perfect square, the two real roots are irrational.