Select all expressions equivalent to (x + 6)^2.

  • x^2 + 36
  • x^2 + 12x + 36
  • x^2 – 12x + 36
  • (x + 6)(x + 6)
  • x^2 + 6x + 36
  • x^2 + 12x + 36
  • (x + 6)(x + 6)

Five times a number decreased by 7 equals 103. Which equation solves the problem?

  • 5x – 7 = 103
  • x/5 – 7 = 103
  • 5x + 7 = 103
  • 7x – 5 = 103
  • 5x - 7 = 103

7 identical pens cost 210 taka. If one pen costs x taka, which equation and value are correct?

  • x + 7 = 210, x = 203
  • x/7 = 210, x = 1470
  • 7x = 210, x = 30
  • 7x = 30, x = 210
  • 7x = 210, x = 30

A father’s age is 4 more than three times his son’s age. If the father is 73, find the son’s age.

  • 27
  • 23
  • 24
  • 69
  • 23


Five times a number decreased by 7 equals 78. Which equation solves the problem?

  • 5x – 7 = 78
  • 5x + 7 = 78
  • x/5 – 7 = 78
  • 7x – 5 = 78
  • 5x - 7 = 78

6 identical pens cost 228 taka. If one pen costs x taka, which equation and value are correct?

  • 6x = 228, x = 38
  • x + 6 = 228, x = 222
  • x/6 = 228, x = 1368
  • 6x = 38, x = 228
  • 6x = 228, x = 38

A father’s age is 4 more than three times his son’s age. If the father is 76, find the son’s age.

  • 25
  • 28
  • 24
  • 72
  • 24

Five times a number decreased by 7 equals 68. Which equation solves the problem?

  • 5x – 7 = 68
  • x/5 – 7 = 68
  • 5x + 7 = 68
  • 7x – 5 = 68
  • 5x - 7 = 68


3 identical pens cost 132 taka. If one pen costs x taka, which equation and value are correct?

  • x + 3 = 132, x = 129
  • 3x = 132, x = 44
  • x/3 = 132, x = 396
  • 3x = 44, x = 132
  • 3x = 132, x = 44

A father’s age is 4 more than three times his son’s age. If the father is 55, find the son’s age.

  • 21
  • 51
  • 18
  • 17
  • 17

Five times a number decreased by 7 equals 23. Which equation solves the problem?

  • x/5 – 7 = 23
  • 7x – 5 = 23
  • 5x + 7 = 23
  • 5x – 7 = 23
  • 5x - 7 = 23