Find the average of the first 40 natural numbers.
Note
Sum of first n natural numbers = [{n(n+1)}/2]
So, sum of first 40 natural numbers = (40×41)/2 = 820
∴ Required average = (20/40) = 20.5
Sum of first n natural numbers = [{n(n+1)}/2]
So, sum of first 40 natural numbers = (40×41)/2 = 820
∴ Required average = (20/40) = 20.5