A monkey climbing up a pole ascends 6 meters and slips 3 meters in alternate minutes. If the pole is 60 meters high, how long will it take the monkey to reach the top?
Note
Net height ascended in 2 min = (6 - 3) = 3 min.
Net height ascended in 36 min = {(3 ÷ 2) ☓ 36}min = 54 min.
In the 37th min, the monkey ascends 6 min and reaches the top
Hence, the total time taken is 37 minutes.