In the expansion of (1x + 1y)^8, find the coefficient of x^7y^1.
Note
Use the binomial theorem and match the power of y to decide the value of k. Once k is known, the power of x is automatically n-k. The general term is C(8,k)(x)^(8-k)(y)^k. For k=1, the coefficient is C(8,1)·1^7·1^1=8. Remember that the numerical coefficient comes from the binomial coefficient and the constants attached to x and y, including any negative sign.
