Simplify: (x^2 – 64)/(x – 8), where x ≠ 8. [Unique SSC algebra item 3]
Note
Look at the numerator first. It is a difference of two squares, so it can be factored before division. Use difference of squares: x^2 - 64 = (x - 8)(x + 8), then cancel x - 8. The condition in the question tells us the cancelled factor is not zero, so cancellation is allowed. Therefore the simplified expression is x + 8.
