What is the vertex of y = 4(x + 5)^2 + 7?
Note
In y = a(x-h)^2+k, the vertex is (h,k). Therefore the vertex is (-5, 7).
What is the vertex of y = 4(x + 5)^2 + 7?
In y = a(x-h)^2+k, the vertex is (h,k). Therefore the vertex is (-5, 7).