Given that HCF(a, b) = 6, LCM(a, b) = 180, and a = 54, find b.
Note
Using a·b = HCF·LCM, we have 54·b = 6·180 = 1080, so b = 1080/54 = 20.
Given that HCF(a, b) = 6, LCM(a, b) = 180, and a = 54, find b.
Using a·b = HCF·LCM, we have 54·b = 6·180 = 1080, so b = 1080/54 = 20.