Find the pair(s) of consecutive integers whose product is 56. Select all correct pairs.
Note
Let n(n+1)=56 gives n^2+n-56=0 with solutions n=7 or n=-8, so the consecutive pairs 7 and 8 and -8 and -7 both have product 56.
Find the pair(s) of consecutive integers whose product is 56. Select all correct pairs.
Let n(n+1)=56 gives n^2+n-56=0 with solutions n=7 or n=-8, so the consecutive pairs 7 and 8 and -8 and -7 both have product 56.