حل المعادلة √(x – 4) = 3.
Correct answer(s):
- 13
Topic
Algebra
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Quizzes in Algebra for HSC
إذا كان α+β=-3 and αβ=5، فأوجد α^3+β^3.
Correct answer(s):
- 18
حل المتباينة (x – (-8))(x – (4)) < 0.
Correct answer(s):
- -8 < x < 4
حل المتباينة (x – (-6))(x – (3)) < 0.
Correct answer(s):
- -6 < x < 3
حل المتباينة (x – (-1))(x – (8)) > 0.
Correct answer(s):
- x 8
حلّل (x – 13)/((x + 1)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- -2/(x + 1) + 3/(x + 8)
حلّل (-4)/((x + 2)(x + 6)) إلى كسور جزئية.
Correct answer(s):
- -1/(x + 2) + 1/(x + 6)
حلّل (3*x + 30)/((x + 6)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- 6/(x + 6) + -3/(x + 8)
حلّل (x + 8)/((x + 4)(x + 6)) إلى كسور جزئية.
Correct answer(s):
- 2/(x + 4) + -1/(x + 6)
حلّل (3*x + 5)/((x + 1)(x + 2)) إلى كسور جزئية.
Correct answer(s):
- 2/(x + 1) + 1/(x + 2)
حلّل (5*x + 11)/((x + 2)(x + 3)) إلى كسور جزئية.
Correct answer(s):
- 1/(x + 2) + 4/(x + 3)
حلّل (-6*x – 40)/((x + 6)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- -2/(x + 6) + -4/(x + 8)
حلّل (4*x + 14)/((x + 2)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- 1/(x + 2) + 3/(x + 8)
حلّل (x + 15)/((x + 3)(x + 5)) إلى كسور جزئية.
Correct answer(s):
- 6/(x + 3) + -5/(x + 5)
حلّل (-2*x – 6)/((x + 4)(x + 5)) إلى كسور جزئية.
Correct answer(s):
- 2/(x + 4) + -4/(x + 5)
حلّل (7*x + 26)/((x + 2)(x + 4)) إلى كسور جزئية.
Correct answer(s):
- 6/(x + 2) + 1/(x + 4)
حلّل (7*x + 47)/((x + 5)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- 4/(x + 5) + 3/(x + 8)
حلّل (-5*x – 37)/((x + 7)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- -2/(x + 7) + -3/(x + 8)
حلّل (2*x + 4)/((x + 5)(x + 7)) إلى كسور جزئية.
Correct answer(s):
- -3/(x + 5) + 5/(x + 7)
حلّل (6*x + 42)/((x + 5)(x + 8)) إلى كسور جزئية.
Correct answer(s):
- 4/(x + 5) + 2/(x + 8)